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tia_tia [17]
3 years ago
13

Pls help me.And can u pls show the steps.Thanks

Mathematics
1 answer:
Kisachek [45]3 years ago
8 0
The answer is
S=4
T=12
R=9

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How do you solve this question and what’s the answer
shutvik [7]

Answer:

7.74 square cm

Step-by-step explanation:

To find the leftovers, calculate the area of the square and the area of the circle. Then subtract the two.

Square: A = s*s = 6*6 = 36

Circle: A = \pi r^2\\A = \pi 3^2\\A = 9 \pi\\A= 28.26

The area leftover is A = 36 - 28.26 = 7.74

4 0
3 years ago
Graph it pleaseeeeeeeeeeeeeeeeeeeeeeeeeeee
mina [271]

Answer:

Step-by-step explanation:

5c + 4f ≥ 200

c + f ≤ 60

c > 0

f > 0

5 0
2 years ago
I need some help with this math question
Vilka [71]
The answer is 63 cm bc 30 60 90 triangles have a rule where the short leg is x longer is x√3 and the hypotenuse is x2
you can see this if you imagine the triangle as equilateral then cutting it in half
6 0
3 years ago
Which person is not living within their means?
Lady bird [3.3K]

The person that is not living within their means is Ella who has maxed out all three of her credit cards but pays the minimum balance each month.

<h3>What does it mean when a person is living above their means?</h3>

If a person is living above their means, the person is spending more money than they have. A person living above their means would most likely borrow in order to afford their lifestyle. A person living above their means would have no amount of savings.

To learn more about credit cards, please check: brainly.com/question/14716152

3 0
2 years ago
Y''+Y'+Y=1<br> solve ordinary differential equation
taurus [48]

Answer:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

Step-by-step explanation:

y" + y' + y = 1

This is a second order nonhomogenous differential equation with constant coefficients.

First, find the roots of the complementary solution.

y" + y' + y = 0

r² + r + 1 = 0

r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)

r = [ -1 ± √(1 − 4) ] / 2

r = -1/2 ± i√3/2

These roots are complex, so the complementary solution is:

y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)

Next, assume the particular solution has the form of the right hand side of the differential equation.  In this case, a constant.

y = c

Plug this into the differential equation and use undetermined coefficients to solve:

y" + y' + y = 1

0 + 0 + c = 1

c = 1

So the total solution is:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

To solve for c₁ and c₂, you need to be given initial conditions.

5 0
3 years ago
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