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Doss [256]
3 years ago
5

A woman is twice as old as her daughter. Twenty years ago, she was four times as old as he daughter. How old are they now? (i do

n’t get this one cuz it’s subtracting instead of adding and it made me confuzzled)
Mathematics
1 answer:
AysviL [449]3 years ago
4 0
So for this, you might want to set up some equations.

The mom's variable is m and the daughter's is d.  

So now is it m=2d

And twenty years ago it was m-20=4(d-20)  which is the same as m-20=4d-80.

Simplify so it is m=4d-60. Now, plug it in as m in the first equation. 

4d-60=2d           2d=60        d=30  

Now, we know that the mom must be 60 and the daughter 30 years old.
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mixas84 [53]

You haven't provided any value, but I can tell you the solution set for the inequality.

First of all, expand both sides:

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Add 3x to both sides:

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18 > 9x

Which is of course equivalent to

9x < 18

Divide both sides by 9

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7 0
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3 years ago
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Step-by-step explanation:

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gavmur [86]
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8 0
3 years ago
Someone help please:
frozen [14]

Answer:

The sharing cone holds about 9 times more popcorn than the skinny cone.

Step-by-step explanation:

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V = \frac{\pi r^{2}h}{3}

r is the radius and h is the inches.

Skinny-size cone:

Radius is r, height h. So

V_{sk} = \frac{\pi r^{2}h}{3}

Sharing size:

Radius is now 3r. So

V_{sh} = \frac{\pi (3r)^{2}h}{3} = \frac{9\pi r^{2}h}{3} = 3\pi r^{2}h

How many times more popcorn?

r = \frac{V_{sh}}{V_{sk}} = \frac{3\pi r^{2}h}{\frac{\pi r^{2}h}{3}} = \frac{3*3\pi r^{2}h}{\pi r^{2}h} = 9

The sharing cone holds about 9 times more popcorn than the skinny cone.

6 0
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