In this, 3.695 to 4, the tenths was rounded
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
i think its an isoceles
Step-by-step explanation:
Answer:
They both equal
Step-by-step explanation:
Answer: The lendor will allow for $1500 for the housing expenses.
This lendor is allowing 30% for the debt. So, we start by multiplying 8000 times 0.3 which equals 2400.
However, we have to subtract the current debts of 900.
2400 - 900 = 1500