Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer:
5026*10^-5
Step-by-step explanation:
Answer:
b=15 g=25
Step-by-step explanation:
lets translate that story problem to mathematics equations
the problem told that no. of girls are 10 more than no of boys so this will =
g=b+10
then in class there are 40 students that means
g+b=40
now we have to equations with two variables then we should substitute
(b+10)+b=40
lets remove the brackets
2b+10=40 subtract 10 from both sides
2b=30 now divide both by 2
b=15 so g=25 after you write the equation once again with the new proof or number
The greatest common factor is 2
We first have to look for the largest number that goes into both equations. The factors of 12 are 1, 2, 3, 4, 6 and 12. None of 3, 4, 6, or 12 go into 26 evenly. So 2 is the largest number you can take out.
With the variables, we take out as many as the lowest number will let us. Since the smallest number of n's is 2 in the second term, we take that many.
Answer:
Yes.
Step-by-step explanation:
It is a function because it passes the vertical line test. Each x-value has just one y-value. If the relation had any x-values that had several y-values, it would just be a relation. But this one is a function.
Hope this helps!
