<span>83 1/5 -108 2/5 - (-99 1/5) = 74</span>
9514 1404 393
Answer:
- relative maximum: -4
- relative (and absolute) minimum: -5
Step-by-step explanation:
The curve has a relative maximum where values on either side are lower. This looks like a peak in the curve. There is one of those on the y-axis at y = -4.
The relative maximum is -4.
__
A relative minimum is a low point, where the curve is higher on either side. There are two of these, located symmetrically about the y-axis. The minimum appears to be about y = -5. (They might be at x = ± 1, but it is hard to tell.)
The relative minima are -5.
__
A minimum or maximum is absolute if no part of the curve is lower or higher. Here, the minima are absolute, while the maximum is only relative. (The left and right branches of the curve go higher than y=-4.)
_____
Identifying the points on the curve should be the easy part. Deciding what the coordinates are can be harder when the graph is like this one.
Answer:
The area of the circle is 379.94 mm²
Step-by-step explanation:
To solve this problem we need to use the area formula of a circle:
a = area
r = radius = 11 mm
π = 3.14
a = π * r²
we replace with the known values
a = 3.14 * (11 mm)²
a = 3.14 * 121 mm²
a = 379.94 mm²
Round to the nearest tenth
a = 379.94 mm² = 379.9 mm²
The area of the circle is 379.9 mm²
9514 1404 393
Answer:
(a, b, c) = (-0.425595, 11.7321, 2.16667)
f(x) = -0.425595x² +11.7321x +2.16667
f(1) ≈ 13.5
Step-by-step explanation:
A suitable tool makes short work of this. Most spreadsheets and graphing calculators will do quadratic regression. All you have to do is enter the data and make use of the appropriate built-in functions.
Desmos will do least-squares fitting of almost any function you want to use as a model. It tells you ...
a = -0.425595
b = 11.7321
c = 2.16667
so
f(x) = -0.425595x² +11.7321x +2.16667
and f(1) ≈ 13.5
_____
<em>Additional comment</em>
Note that a quadratic function doesn't model the data very well if you're trying to extrapolate to times outside the original domain.
