Answer:
33333
Step-by-step explanation:
C = 2m^2 + m
D = 2 - 6m + 2m^2
2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2
2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4
since LM=LN there values are same which is given as 5.5 cm and MN =7cm
now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!
Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.
<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>
He moved it at 30ft./minute
<span>The coterminal angles of angle A are given by adding k times 360° to it, where k is an integer, positive or negative.
Similarly, all angles that are coterminal with 141° are given by
141° + k * 360° where k is a positive or negative integer.
That is 141° + 360°, 141 + 2*360° , 141+3*360° and so on
and 141° - 360°, 141° -2*360°, 141° - 3*360° and so on.
9720)</span>
