Your simplified expression is 16s + 2
According to Vieta's formula, if
are solutions of quadratic equation
, then:
In our case:
Answer:: D(t)= 50(4/5)^t
Step-by-step explanation: If 1/5 of the temperature difference is lost each minute, that means 4/5 of the difference remains each minute. So each minute, the temperature difference is multiplied by a factor of 4/5 (or 0.8).
If we start with the initial temperature difference, 50° Celsius, and keep multiplying by 4/5, this function gives us the temperature difference t minutes after the cake was put in the cooler.
