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3 years ago

9

A school has an aquarium in each room. Each aquarium has 2 catfish for every 3 angelfish. How many fish are in an aquarium that

has 6 catfish?

2 answers:

harkovskaia [24]3 years ago

8 0

2 x ? = 6 catfish. (?=3) so multiply everything by 3......3 x 3 = 9 angelfish!!

artcher [175]3 years ago

5 0

Answer:

15

Step-by-step explanation:

2:3 ratio

if there is 2 catfish in a tank, in order to reach 6 catfish, we need 3 tanks

therefore, 3*3=9, 9 is the amount of angel fish

6+9=15

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Let a4+a8+a12+a16=224. Find the sum of first 19 term in sequence.

Tomtit [17]

Without knowing anything about the sequence, this is impossible to answer. But suppose the sequence is arithmetic, in which case each term differs by some constant $k$ :

$a_2=a_1+k$

$a_3=a_2+k=a_1+2k$

$a_4=a_3+k=a_1+3k$

$\ldots$

$a_n=a_{n-1}+k=a_1+(n-1)k$

Then we can write

$a_4+a_8+a_{12}+a_{16}=4a_1+36k=224\implies a_1+9k=56$

and from the formula above, we see this means the 10th term in the sequence is $a_{10}=56$ . But that's all the specific info we can gather about such an arithmetic sequence. If we set the first term to be some unknown $a_1=a$ , then the sum of the first 19 terms in the sequence would be

$\displaystyle\sum_{n=1}^{19}a_n=\sum_{n=1}^{19}\big(a+(n-1)k\big)=19a+k\sum_{n=1}^{18}n=19a+171k$

If we knew one more term in the sequence, we could determine the value of $k$ and derive the value of $a$ (if the first term $a_1$ is not immediately given), and then go on to find an exact numeric value for the sum.

7 0

3 years ago

In the Itty Bitty High School, there are 85 students. There are 27 students who take French, 51 who take Geometry and 38 who tak

andrew-mc [135]

Answer:

58 students

Step-by-step explanation:

Given

$Total = 85$

$French = 27$

$Geometry = 51$

$History = 38$

$None = 5$

$All = 2$

Required

Students that take only 1 subjects

The attached image illustrates the question.

For French only (x), we have:

$x + 7 -2+10-2+2=27$

$x + 15=27$

Collect like terms

$x =- 15+27$

$x =12$

For Geometry only (y), we have:

$y+10-2+15-2+2=51$

$y+23=51$

Collect like terms

$y=-23+51$

$y=28$

For History only (z), we have:

$z +15-2+7-2+2=38$

$z +20=38$

Collect like terms

$z =-20+38$

$z =18$

Students with one subject is then calculated as:

$1\ subject = x+y+z$

$1\ subject = 12 + 28 + 18$

$1\ subject = 58$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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