Question

May you help me with this please! 6x%2B3y%3D-3%7D%7D%20%5Cright." id="TexFormula1" title="\left \{ {{4x+3y=-5} \atop {6x+3y=-3}} \right." alt="\left \{ {{4x+3y=-5} \atop {6x+3y=-3}} \right." align="absmiddle" class="latex-formula">

Answer 1

Answer: x = 1 and y = -3

The two lines cross at the point (x,y) = (1,-3) as shown in the graph below.

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Explanation:

Subtract the equations. Subtract straight down.

The x terms subtract to get 4x-6x = -2x

The y terms subtract to get 3y-3y = 0y = 0, the y terms cancel out

Subtract the constant terms on the right side of each equation: -5 minus -3 = -5 + 3 = -2

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After those three subtractions, we end up with the new equation -2x = -2

Divide both sides by -2 to fully isolate x, to go from -2x = -2 to x = 1

Now use x = 1 to find the value of y

4x + 3y = -5

4(1) + 3y = -5 ... replace x with 1

4 + 3y = -5

4+3y-4 = -5-4 ... subtract 4 from both sides

3y = -9

3y/3 = -9/3 ... divide both sides by 3

y = -3