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3 years ago

What’s the median of 1,1,7,3,2,2,3,5

Mathematics

2 answers:

Sloan [31]3 years ago

8 0

I think the answer is 3and2

Ratling [72]3 years ago

3 0

3,2

That’s the answer

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write about how many rotations does the bike wheel make when the bike travels 1 mile explain or show your reasoning

tatuchka [14]

Answer:

it takes 11,600

Step-by-step explanation:

because a mile is 5,280 feet and both of you feet are moving the wheels and that should be multiplied by 2.

7 0

3 years ago

What is the y intercept of the parabola y = x2 + 22/5

maksim [4K]

Answer:

The y-intercept is 4.4

Step-by-step explanation:

See picture below.

7 0

3 years ago

Did the first one need help with the last few

Otrada [13]

Hi there! :)

a) (ii) The two angles are vertical angles, so they are congruent.

b)(i) y = 71°

(ii) The two angles are alternate interior angles, so they are congruent.

c) z = 44°

(ii) m∠x = 65° because the two angles are vertical angles, so they are congruent.

b) (i)

∠y is an alternate interior angle, therefore:

m∠y = 71°

c) Use the sum of interior angles of a triangle to determine the measure of angle z:

180 = 65 + 71 + z

180 = 136 + z

180 - 136 = z

z = 44°.

7 0

3 years ago

When do we flip an inequality?

tatuchka [14]

Answer:

When multiplying and dividing it by a negative

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta$

and so the second derivative is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta$

4 0

3 years ago