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3 years ago

What is the ratio of ounces to pounds

Mathematics

2 answers:

zhenek [66]3 years ago

8 0

One pound is 16 ounces so 16:1

kompoz [17]3 years ago

4 0

Answer: 16 ounces : 1 pound

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Avaluate 2^3x-1 for x=1

DENIUS [597]

Answer:

4 or 7 (Check the explanation to see which one your equation actually is.

Step-by-step explanation:

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was $2^{3x-1}$ or $2^{3x}-1$ , so I'll be doing both:

For $2^{3x-1}$ , we should plug in x to get $2^{3(1)-1}$ and then simplify to get $2^{2}$ .

2 to the power of 2 or $2^{2}$ is equal to 2 * 2 or 4.

The second one, $2^{3x}-1$ , we should plug in x to get $2^{3(1)}-1$ and then to become $2^{3}-1$ . 2 to the power of 3 or $2^{3}$ is 8 and then minus 1 is 7.

7 0

3 years ago

Read 2 more answers

Need help anything helps thanks

yKpoI14uk [10]

A binomial squared is written like

$x^2+2ax+a^2$

So, we have $2a=6 \iff a=3$

So, we want to complete the square $(x+3)^2 = x^2+6x+9$

We can add and subtract 9 to write

$x^2+6x = x^2+6x+(9-9) = (x^2+6x+9)-9 = (x+3)^2-9$

5 0

3 years ago

WILL MARK BRAINLIEST

dsp73

<h3>Refer to the diagram below</h3>

Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.

Refer to the diagram below for examples of what I mean.

5 0

3 years ago

What is the standard form for 200,000+80,000+700+6

ozzi

280,706 is the standard form

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=2x%28x%20-%202%29%5E%7B2%7D%20%20%2B%203x%28x%20%2B%203%29%5E%7B2%7D%20%20-%20x%5E%7B2%7D%20%2

Ratling [72]

= x·[2(x²- 4x + 4) + 3(x² + 6x + 9) - x² + 5x]

= x(2x² - 8x + 8 + 3x² + 18x + 27 - x² + 5x)

= x(4x² + 15x + 35)

5 0

3 years ago