Answer: g(1-t)=3t^2-t-1
Step-by-step explanation:
g(x)=3(x)^2-5(x)+1
g(1-t)=3(1-t)^2-5(1-t)+1
g(1-t)=3(1-t)(1-t)-5-(-5t)+1
g(1-t)=3(1-t-t+t^2)-5+5t+1
g(1-t)=3(1-2t+t^2)-5+5t+1
g(1-t)=3-6t+3t^2-5+5t+1
g(1-t)=3-5+1-6t+5t+3t^2
g(1-t)=-1-t+3t^2
g(1-t)=3t^2-t-1
If you have a graphing calculator just put in the equation in 'y=' (not the i equation), and then go to 2nd trace and see where the y=0, those numbers under the x column are the zeros. For the first one, the zeros are: -1, .5, and 2.8. For the second question the zeros are: -3 and about 1.9. The zeros with a decimal are estimations.
Answer: Raju travels at a higher speed.
Step-by-step explanation:
Speed inversely proportional to time.
As time taken to cover a particular distance decreases the speed will increase.
Raju covers a certain distance in 1 hour.
Sham covers the same distance in 2 hours.
1< 2
Thus Raju travels at a higher speed.
Answer:
b1=
b2=
Step-by-step explanation:
