![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=23.9\\ h=100 \end{cases}\implies V=\cfrac{\pi (23.9)^2(100)}{3} \\\\\\ V=\cfrac{57121\pi }{3}\implies V\approx 59816.97\implies \stackrel{\textit{rounded up}}{V=59817} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D23.9%5C%5C%20h%3D100%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%2823.9%29%5E2%28100%29%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20V%3D%5Ccfrac%7B57121%5Cpi%20%7D%7B3%7D%5Cimplies%20V%5Capprox%2059816.97%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7BV%3D59817%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
now, for the second one, we know the diameter is 10, thus its radius is half that or 5.
![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5\\ V=225 \end{cases}\implies 225=\cfrac{\pi (5)^2 h}{3}\implies 225=\cfrac{25\pi h}{3} \\\\\\ \cfrac{225}{25\pi }=\cfrac{h}{3}\implies \cfrac{9}{\pi }=\cfrac{h}{3}\implies \cfrac{27}{\pi }=h\implies 8.59\approx h\implies \stackrel{\textit{rounded up}}{8.6=h}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D5%5C%5C%20V%3D225%20%5Cend%7Bcases%7D%5Cimplies%20225%3D%5Ccfrac%7B%5Cpi%20%285%29%5E2%20h%7D%7B3%7D%5Cimplies%20225%3D%5Ccfrac%7B25%5Cpi%20h%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B225%7D%7B25%5Cpi%20%7D%3D%5Ccfrac%7Bh%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B9%7D%7B%5Cpi%20%7D%3D%5Ccfrac%7Bh%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B27%7D%7B%5Cpi%20%7D%3Dh%5Cimplies%208.59%5Capprox%20h%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B8.6%3Dh%7D)
Hey there,
This question is asking us to find the slope using the given points. In order to do that we use the equation:
Now we use the points and plug them into the equation above:
=
Therefore the slope of the line that passes through the points (-7, 5) and (-2, 3) would be 
Hope I helped,
Amna
Let us start with the unknown. Let us give one of the base angles the
value of x. The other base angle is also x since both the base angles in
an isosceles triangle will be equal. The remaining angle is 40 more
than three times one of the base angles.It is 3x + 40. Here we get the
equation
x+x+3x+40=180
5x + 40 = 180
5x = 180 - 40 = 140
Therefore x = 140/5 = 28
So the angles are 28, 28 and 124.
The third angle is 3 times 28 + 40 = 84 + 40 = 124.
Twenty two is less than x