For rigt triangle with legs legnth a and b and hypotnuse legnth c
a^2+b^2=c^2
we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller
ok so
first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and
hypontuse is 6 more than shorter
c=6+b
sub 3+b for a and 6+b for c in oroiginal equation'
a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero
b-9=0
b=9
b+3=0
b=-3
fasle, legnths cannot be negative
answer is shorter side=9 cm
Answer:
Step-by-step explanation:
True y=2x+1 and y-3x=4 it would be the same way because you can solve for x and you can solve for y
Answer:
- 3y² - 7y + 6
Step-by-step explanation:
Given
(- 3y + 2)(y + 3)
Each term in the second factor is multiplied by each term in the first factor, that is
- 3y (y + 3) + 2(y + 3) ← distribute both parenthesis
= - 3y² - 9y + 2y + 6 ← collect like terms
= - 3y² - 7y + 6
