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DanielleElmas [232]
3 years ago
12

Sin(x+22)°=cos(2x−7)°

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
8 0
To answer this, it must be noted that the trigonometric functions sine and cosine will have the same values if the angles are complementary (meaning, their sum is 90°). 
                                         90 = (x + 22) + (2x - 7)
The value of x from the equation is 25. 
Diano4ka-milaya [45]3 years ago
3 0

Answer:

x = 25

Step-by-step explanation:

Given : \sin (x+22)^{\circ}=\cos (2x-7)^{\circ}

We have to find the value of x.

Consider the given  \sin (x+22)^{\circ}=\cos (2x-7)^{\circ}

We know,

\sin\theta=\cos(90^{\circ}-\theta)

Consider the left side  \sin (x+22)^{\circ}=\cos(90^{\circ}-(x+22)^{\circ})

thus,

\sin (x+22)^{\circ}=\cos (2x-7)^{\circ} becomes,

\cos(90^{\circ}-(x+22)^{\circ})=\cos (2x-7)^{\circ}

Simplify for x,

\cos(68-x)=\cos (2x-7)

Thus, 68 - x = 2x - 7

Adding x both side , we have

68 = 3x - 7

Adding 7 both side, we have,

75 = 3x

Divide both side by 3, we have,

x = 25

Thus, x = 25

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I assume your problem statement actually says

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Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
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