Answer:
x = 9 and y = 1
Step-by-step explanation:
Here,
x = 10 - y and y = x - 8 is given
then, name the equation
x = 10 - y ...(1)
y = x - 8 ...(2)
Now, put the value of x in equation (2) we get
y = x - 8
y = (10 - y) - 8
y = 10 - y - 8
y + y = 10 - 8
2y = 2
y = 2÷2
y = 1
Here, we get the value of y = 1
Now, we put the value of y in equation (1) we get
x = 10 - y
x = 10 - (1)
x = 10 - 1
x = 9
<h3>
<em><u>VERIFICATION</u></em><em><u>:</u></em></h3>
x = 10 - y
9 = 10 - 1
9 = 9
Hence, LHS = RHS
-TheUnknownScientist
Answer:
If I read it right I believe it's C.
Step-by-step explanation:
Answer:
a b c
Step-by-step explanation:
First, factor out a 3.
3(x² - 9)
In any quadratic ax² + bx + c, we can split the bx term up into two new terms which we want to equal the product of a and c.
In this case, we have x² + 0x - 9. (the 0x is a placeholder)
We want two numbers that add to 0 and multiply to get -9.
Obviously, these numbers are 3 and -3.
Now we have 3(x² + 3x - 3x - 9).
Let's factor.
3(x(x+3)-3(x+3))
<u>3(x-3)(x+3)</u>
There are multiple shortcuts which you could make here, FYI:
Instead of splitting the middle, if your a value is 1, you can go straight to that step (x+number)(x+other number).
Whenever you have a difference of squares, like a²-b², that factors to (a+b)(a-b).
