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kotykmax [81]
3 years ago
8

There are 3 consecutive integers. The third integer subtracted from the sum of the first two integers equals 9. What is the midd

le integer ?
Mathematics
1 answer:
Alexus [3.1K]3 years ago
3 0

Answer:

The middle integer is 11.

Step-by-step explanation:

Hi there!

Let <em>x</em> be the smallest of the three consecutive integers.

Let <em>x</em>+1 and <em>x</em>+2 be the next consecutive integers. This makes <em>x</em>+1 the middle integer.

We're given that the third integer subtracted from the sum of the first two integers equals 9. We can use this to construct an equation:

(x)+(x+1)-(x+2)=9

Combine like terms:

x+x+1-x-2=9\\x+x-x+1-2=9\\x-1=9\\x=10

Therefore, the smallest integer is 10.

Because the middle integer is <em>x</em>+1, the middle integer is 11.

I hope this helps!

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Vsevolod [243]
Short Answer 10
The tough part is the number of drinks.
Let the number of them be x
4.5 x + 3 + (10/100) * (4.5x + 3) + (7/100) * (4.5 x + 3) ≤  60

The tip is not included in the tax, and the tax does not include the tip. You can shorten this up quite a bit.
4.5 x + 3 + (10/100) * (4.5x + 3) + (7/100) * (4.5 x + 3) ≤  60
(1 + 10/100 + 7 /100) (4.5x + 3) ≤  60     Combine the tax, tip, scone and Lattes 

(1.17) * (4.5x + 3) ≤ 60                            Divide by 1.17
4.5x + 3 ≤ 60 / 1.17 
4.5x + 3 ≤ 51.28                                      Subtract 3
4.5x ≤ 48.28                                            Divide by 4.5
x ≤ 48.28 / 4.5
x ≤ 10.72 

Discussion.
There's a problem. He can't buy 0.72 of a Latte. He can only buy 10 of them. In this case we must round down so what happens if he buys 10 lattes? Does the price the taxes and the tip allow him to get another Latte? The answer should be no because then you would be 11 lattes and the tip and taxes would push you over 60 dollars. But be careful, sometimes things like this can alter you answer.. 

Answer: 10 <<<<
7 0
3 years ago
.875 written as a percentage
Alex17521 [72]

Answer:

87.5%

Step-by-step explanation:

to write a percentage as a number you move the decimal to the left 2 times.

7 0
3 years ago
Read 2 more answers
If one of the angels of a triangle is 127 it’s called
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Answer:

obtuse triangle

Step-by-step explanation:

only one angle in a triangle has to be over 90 degrees for it to be and obtuse triangle

hoped this helped

7 0
3 years ago
The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
I am not sure about this problem?
uranmaximum [27]
The answer for your question is 4x^2-15x+6+ 2/3x+5
3 0
3 years ago
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