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slamgirl [31]
3 years ago
9

Danny selects a glass bottle from the shelf randomly without looking and then tosses the fair coin. What is the probability that

he will select a purple glass bottle and that the coin will land heads up?
Mathematics
1 answer:
Kryger [21]3 years ago
4 0
How many of each color bottle and how many colors
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Need help with this math question 30 points correct answers only pls
Likurg_2 [28]

its the third answer

Step-by-step explanation:

and its only 5 points not 30

3 0
3 years ago
Read 2 more answers
PLEASE SOLVE THANK YOU :)
Andrej [43]

Answer:

1. 7

2. 35

3 & 4. 7x = 70

5. 10

Step-by-step explanation:

7 0
2 years ago
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If f Subscript x​(a,b)equals f Subscript y​(a,b)equals​0, does it follow that f has a local maximum or local minimum at​ (a,b)?
Anna [14]

Answer:

D.

Step-by-step explanation:

The point must be a critical point but it could be a saddle point. If the point is a saddle point it would not be neither a maximum nor a minimum. So it must be critical but it does not follow directly that it has a local maximum or local minimum.

Therefore D. (a,b) would be a candidate, but is not necessarily a maximum or minimum. It could be a saddle.

5 0
3 years ago
1. Look at the table.
Bezzdna [24]

Answer:

D

Step-by-step explanation:

On the X side they add 2 every time to reach the next number needed. For example if it was to keep going the nect x would be 13

4 0
2 years ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 6%
Georgia [21]

Answer:

a

\% E =  0.9 \%

b

\%E_1 = 10.1 \%

Step-by-step explanation:

From the question we are told that

The probability that an employees suffered lost-time accidents last year is P(e) =  0.06

The probability that an employees suffered lost-time accident during the current year is

P(c) =  0.05

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

P(c | e) =  0.15

Generally the probability that an employee will experience lost time in both year is mathematically represented as

P(c \ n \ e) =  P(e) *  P(c \ |\ e)

=> P(c \ n \ e) =  0.06*   0.15

=> P(c \ n \ e) = 0.009

Generally the percentage of employees that will experience lost time in both year is mathematically represented as

\% E =  P(e \ n \ c ) * 100

=> \% E =  0.009 * 100

=> \% E =  0.9 \%

Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

P(e \ u \ c) =  P(e) + P(c) - P(e \ n \  c)

=> P(e \ u \ c) =  0.06 + 0.05 - 0.009

=> P(e \ u \ c) =  0.101

Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

\%E_1 = P(e \ u \ c) *  100

=> \%E_1 = 0.101*  100

=> \%E_1 = 10.1 \%

7 0
3 years ago
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