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Oxana [17]
3 years ago
14

30+5y_>4x I need the answer ASAP

Mathematics
1 answer:
Gre4nikov [31]3 years ago
5 0
30+5y_>4x
5y_>4x-30
The answer is: y_>(4/5)x-6
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HELP ME Write and solve a proportion to find y.
Phoenix [80]

Given:

A figure of dilation and the center of dilation is O.

To find:

The value of y.

Solution:

The distance between center and vertex of image (d') is proportional to the distance between center and the corresponding vertex of original figure (d).

d'\propto d

d'=kd

\dfrac{d'}{d}=k

Where, k is the scale factor or constant of proportionality.

So, the scale factor for the given dilation is

k=\dfrac{OB'}{OB}

k=\dfrac{36}{16}

k=\dfrac{9}{4}

We know that,

k=\dfrac{\text{Side length of image}}{\text{Corresponding side length of original figure}}

\dfrac{9}{4}=\dfrac{A'C'}{AC}

\dfrac{9}{4}=\dfrac{27}{y}

9\times y=27\times 4

Divide both sides by 9.

y=\dfrac{27\times 4}{9}

y=3\times 4

y=12

Therefore, the value of y is 12.

6 0
3 years ago
Solve by factorising<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="abs
Paladinen [302]

Step-by-step explanation:

\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

\underline{ \underline{ \text{Let's \: solve}}} :

\tt{ {x}^{2}  + 16x +  55 = 0}

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ \tt{ {x}^{2}  + (11 + 5)x + 55 = 0}

⤑ \tt{ {x}^{2}  + 11x + 5x +  55 = 0}

⤑ \tt{x(x + 11) + 5(x + 11) = 0}

⤑ \tt{(x + 5)(x + 11) = 0}

Either :

\tt{x + 5 = 0 \: \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \: Or :  \:  \:  x + 11 = 0}

\sf{⟶ x  = 0 - 5} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:⟶  x =  0 - 11

\tt{⟶x =  - 5 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:     \:  \:⟶   x =  - 11

\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer :  \boxed{ \underline{  \bold{ \tt{x  =  - 5 \: , - 11}}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

6 0
3 years ago
What is the solution for 4.2=c/8?
musickatia [10]
4.2 = <u>c
</u>         8
<u>
<em /></u><em>multiply both sides by 8
</em>
4.2* 8 = <u>8</u><u>c
</u>             8
<u>
</u> c = 33.6<u>
</u>
5 0
3 years ago
Write a mixed number that equivalent to16÷3
poizon [28]
The answer is 5 1/3.
4 0
3 years ago
Are (121 over 11),(23 over 3), and (85 over 5) in simplest form?
Sedaia [141]
Answers:

121/11=11

23/3=23/3

85/5=17
5 0
3 years ago
Read 2 more answers
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