<u>f(x) = x + 3</u>
f(2) = 2 + 3
f(2) = 5
f(4) = 4 + 5
f(4) = 9
f(6) = 6 + 5
f(6) = 11
{(2, 5), (4, 9), (6, 11)}
can also be written as 2i
where i = √-1
Rationalizing denominator,
Answer:
Step-by-step explanation:
All you need o divide 3,300 by 50
3300
÷ 50
--------------
66
so ever minute he would most likely type 66 words
Answer:
Let the base be p
Hypotenuse = 2p +6
Perpendicular = 2p + 4
By Pythagoras theoram
(2p+6)^2 = (2p+4)^2 +p^2
=> 4p^2 +36 + 24p = 4p^2 + 16 +16p +p^2
=> 36+ 24p = p^2 + 16p + 16
=> p^2 - 8p - 20 = 0
=> p^2 - 10p +2p - 20 = 0
=> p(p-10) +2(p-10) = 0
=> (p-10)(p+2) = 0
p = 10 and - 2
Length can't be negative
So,
p = 10
Base = 10
Perpendicular = 24
Hypotenuse = 26
Answer:
True
Step-by-step explanation:
First statement
[a b c | d][x]
[a b c]x=d
ax+bx+cx=d
Second statement
Ax=d
Given that A = [a b c]
[a b c]x=d
ax+bx+cx=d
ax+bx+cx=d
Then, they are going to have the same solutions
