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2 years ago

10

(7,-1) and (6, 6)

1 answer:

vova2212 [387]2 years ago

3 0

Answer:

y=-7x+48 slope would be -7

Step-by-step explanation:

Used a Regression Calculator

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Which of the following is NOT equivalent to 240/300

Lyrx [107]

Two fractions are said to be equivalent if both the numerator and the numerator of one fraction can be obtained by multiplying or dividing the numerat.or and denominator of the other fraction by a single factor.

Dividing the numerator and denominator of 240/300 by 5 gives 48/60
Dividing the numerator and denominator of 240/300 by 60 gives 4/5
Dividing the numerator and denominator of 240/300 by 10 gives 24/30

Whereas dividing 300 by 2 gives 150 dividing 240 by 2 will not give 122. so 122/150 is not equivalent to 240/300.

7 0

3 years ago

Question 8 (1 point)

AleksandrR [38]

Answer:

solution is x=3

Step-by-step explanation:

$logx-log3=log(x-2)$

apply log property

log a- log b= log a/b

$logx-log3=log(x-2)\\log (\frac{x}{3} )=log(x-2)$

we have log on both sides

so we remove the log and make the arguments equal

$\frac{x}{3} = x-2$

solve for x, multiply whole equation by 3

$x=3(x-2)\\x=3x-6\\x-3x=-6\\-2x=-6\\x=3$

now plug in 3 for x and check

$logx-log3=log(x-2)\\log3-log3=log(3-2)\\0=0$

solution is x=3

8 0

3 years ago

Please help it is my birthday !!!

Firlakuza [10]

Answer:

happy birth day to me

Step-by-step explanation:

its F was i close

5 0

2 years ago

A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

3 0

3 years ago

Twenty customers bought the portable drill when it was on sale. Twelve of

vekshin1

Answer:

x+y = t

Step-by-step explanation:

7 0

2 years ago