Answer:
second difference
Step-by-step explanation:
The differences of the y-values will differ by a common amount.
<u>Example</u>:
y = x^2 for x = 2, 4, 6, 8
y-values are 4, 16, 36, 64
differences of these are 12, 20, 28
differences of these differences are 8 and 8, a common value.
The answer is <span>length = 10 yd, width = 2 yd
proof
</span><span>The length of the playground is 5 times longer than its width, it means
l=5w, but 10= 2x5 so we can write l= 5w,
and Area = 20 =l x w = (5x2) x 2 =20</span>
Answer:
7.96 ft
Step-by-step explanation:
Given;
Length of ramp L = 8 ft
Angle with the horizontal (ground) = 6°
Applying trigonometry;
With the length of ramp as the hypothenuse,
The horizontal distance d as the adjacent to angle 6°
Since we want to calculate the adjacent and we have the hypothenuse and the angle. We can apply cosine;
Cosθ = adjacent/hypothenuse
Substituting the values;
Cos6° = d/8
d = 8cos6°
d = 7.956175162946
d = 7.96 ft
The building is 7.96ft away from the entry point of the ramp.
1) Find the radius of the circle. You can do that by inspection; no work required.
2) Use the "area of a circle" formula A = pi r^2 to calculate the area.
3) Round off your area calculation to the nearest hundredth.
Answer:
b=3
Step-by-step explanation:
2b+4b=12
6b^2=12
6b^2 - 6 =12 - 6
b^2/2=6/2
b=3
