Why is 1.71x10^7 written in standard form

A triangle has sides measuring 1.5 m, 2 m and 2.5 m. Show that this is a right-angled triangle.

Nady [450]

Answer:

Yes, this is a right triangle

Step-by-step explanation:

Plug the values into the pythagorean thm.

1.5^2 + 2^2 = 2.5^2

2.25+4=6.25

6.25=6.25

7 0

3 years ago

Identify the interval that is not equal to the other three 15-19 30-34 40-45 45-49

Lunna [17]

Answer:

45-40

Step-by-step explanation:

The first interval is 15-19.

The width of this interval is: 19-15=4

The second interval is 30-34.

The width of this interval is: 34-30=4

The third interval is 40-45.

The width of this interval is: 45-40=5

The fourth interval is 45-49.

The width of this interval is: 49-45=4

<h3>Therefore the interval that is not equal to the other three is 45-40</h3>

5 0

2 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

I NEEDDD HELPPPP ASAPPPP ITS URGENTTT!!!!

natulia [17]

Answer:

(x-6)^2+(y-14)^2=4

Step-by-step explanation:

7 0

2 years ago

JESUS I DONT GET THIS SOMETIMES, PEOPLE BE LIKE "X=69420" WHEN THE PROBLEM IS IN GRAPH FORM IM SO CONFUSED LIKE IM SORRY THAT WE

puteri [66]

Answer:

Equation: y = -3x -2

Graph: Attached below ↓↓↓↓↓

Step-by-step explanation:

The equation is y = -3x + b

We need B at this point.

Since we have a point given to us,( -2, 4)we can input the x and y

Solve:

4 = -3(-2) + b

4 = 6 + b

b = -2

So the equation we have is y = -3x -2

Let's graph the line.

We go 2 units below the x-axis, because the y-intercept is -2, and the slope is -3, so we go down 3 units, and to the right 1.

Picture attached:

-Chetan K

4 0

2 years ago