Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
Tan theta = 12/5
Hope it helps.
Answer:
A general line can be represented as , y= m x + c
And general equation of circle is , ax²+by²+2 g x +2 f y +c=0
Now there are following possibilities
1. A line and circle have no common point of intersection, that is no solution.
2. A line may be a tangent to a circle, that is one common point, one solution.
3. A line may intersect a circle maximum at two points, that is 2 solution.
Image is depicted below.
Answer:
Step-by-step explanation:
Given sequence: 
Therefore,
General form of an arithmetic sequence: 
(where a is the first term and d is the common difference)
To find the common difference, subtract a term from the next term:
Therefore,
To find the 6th term, input n = 6 into the equation:
They are equal in mass.
<u>1 kilogram is 1,000 grams.</u>
Meaning, 6,000 grams is 6 kilograms.
