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Yuliya22 [10]
3 years ago
15

Which of the following linear expressions CANNOT be factored?

Mathematics
2 answers:
faust18 [17]3 years ago
5 0
(A) cannot be factored 
mrs_skeptik [129]3 years ago
4 0
A) 15x+22

It cant be factored with rational numbers.
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1. The radius equals<br> units<br> 2. The diameter equals<br> units
Lelu [443]

Answer:

radius = 4units

diameter = 8units

Step-by-step explanation:

The radius is the distance from the midpoint of a circle to any point on the side of the circle. In this case, the radius is, 4units. The diameter is twice the radius and is 8 units.

8 0
3 years ago
HELP ON 7,8,9,10 <br><br> EXPLAIN OR GIVE ME HINTS NO ANSWERS
aliya0001 [1]
7. Try drawing 2 lines parallel from each other. What shape do you think of first?
8. To find the perimeter, you add up all of the sides.
9. A parallelogram has 2 pairs of parallel sides.
10. A rhombus is basically a square; all even sides. A rectangle has 2 pairs of parallel sides and the sides are not all the same. 
7 0
3 years ago
Why is -a² is always negative (a ≠ 0) and why is (-a)² is always positive?
hjlf
-a^2=(-1)\cdot a\cdot a

Regardless of the sign of a, we have a\cdot a=a^2\ge0 (never negative). But multiplying by -1 makes it negative.

On the other hand,

(-a)^2=((-1)\cdot a)^2=(-1)^2\cdot a^2=1\cdot a^2=a^2

which can never be negative for real a.
6 0
3 years ago
What are the solutions to this system of equations?
saveliy_v [14]

Answer:

A

Step-by-step explanation:

The solution is at the points of intersections of the graphs

The graphs intersect at (- 3, 0 ) and (2, 5 )  , then

solutions are (- 3, 0 ) and (2, 5 )

4 0
2 years ago
A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg
polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

P(X = x) = nCx p^{x} q^{n - x}

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662

Finally, the probability that 2 or fewer students will withdraw is

P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355

b) Compute the probability that exactly 4 will withdraw.

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0
3 years ago
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