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4 years ago

X2 + 3x - 108 = 0 What is the answer?

Mathematics

1 answer:

worty [1.4K]4 years ago

5 0

Answer:

The answer is x=9 and/or x = -12

Step-by-step explanation:

This is a quadratic formula meaning that you must take the a value (1) b value (3) and the c value (108) and plug it into the quadratic formula.

$\frac{-3±\sqrt{9+4*1*-108} }{2}$

which simplifies to -3 add or subtract the sqrt of 441 divided by two.

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Amy deposits $360 in an account that pays 1/2% simple annual interest. How much interest will she earn in 6 years?

12345 [234]

Answer:

Amy will earn $343.04

7 0

3 years ago

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

3 years ago

Nter the equation of the line in slope-intercept form. Slope is 6, and (1, 3)

kupik [55]

Answer:

The equation in the slope-intercept form will be:

$y=6x-3$

Step-by-step explanation:

Given

slope = m = 6

point = (1, 3)

As we know that the equation of a line in point-slope form is

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 6 and point = (1, 3)

$y-3=6\left(x-1\right)$

Writing the equation in slope-intercept form

$y=mx+b$

where m is the slope, and b is the y-intercept

so the equation of the line in slope-intercept form becomes

$y-3=6\left(x-1\right)$

add 3 to both sides

$y-3+3=6\left(x-1\right)+3$

$y=6x-3$

Therefore, the equation in the slope-intercept form will be:

$y=6x-3$

6 0

3 years ago

The hypotenuse of a 45°-45°-90° triangle measures 128 cm. A right triangle is shown. The length of the hypotenuse is 128 centime

Aleks [24]

Answer:

64√2 or 64 StartRoot 2 EndRoot

Step-by-step explanation:

A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.

Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.

X=(128√2)/2= 64√2 cm.

Since X is the leg, the answer would be 64√2

3 0

3 years ago

Read 2 more answers

Evaluate each expression if a = 4.1, b = 5.7, and c=0.3. 4. a+b-c 5. 10-(a+b) 6. B- c+2

posledela

Answer:

a+b-c = 9.5

10-(a+b) = 0.2

b-c+2 = 7.4

Step-by-step explanation:

Given the expression

a+b-c

a=4.1

b=5.7

c=0.3

substituting the values in the expression

a+b-c = 4.1+5.7-0.3

= 9.8 - 0.3

= 9.5

Given the expression

10-(a+b)

a=4.1

b=5.7

c=0.3

substituting the values in the expression

10-(a+b) = 10 - (4.1+5.7)

= 10 - 9.8

= 0.2

Given the expression

b-c+2

a=4.1

b=5.7

c=0.3

substituting the values in the expression

b-c+2 = 5.7 - 0.3 +2

= 5.4 + 2

= 7.4

7 0

3 years ago