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3 years ago

Uestion Hel

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

6 0

40ft hope this hellped ask again

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The enrollment at Sonya's school is 109% of last years enrollment. What decimal represents this year's enrollment to last year's

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What is the percent change if the student population of the school goes from 380 students to 335 students? Round to the nearest

lys-0071 [83]

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Step-by-step explanation:

I'm srry if I'm wrong but I'm 90-ish% its correct

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10 to the power of 2 divided by 4 divided by 3 plus 2

mylen [45]

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3 years ago

Using the simple random sample of weights of women from a data set, we obtain these sample statistics: nequals45 and x overbar

Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : $n=45$

$\overline{x}=148.79\text{ lb}$

$\sigma=31.37\text{ lb}$

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = $\mu=148.79\text{ lb}$

b) The confidence interval for the population mean is given by :-

$\mu\ \pm E$ , where E is the margin of error.

Formula for Margin of error :-

$z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Significance level : $\alpha=1-0.90=0.1$

Critical value : $z_{\alpha/2}=z_{0.05}=\pm1.645$

Margin of error : $E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69$

Now, the 90% confidence interval for the population mean will be :-

$148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)$

Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0

3 years ago