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kvasek [131]
3 years ago
10

A triangle has vertices (-1,2), (3,1), and (7,2). What is the approximate perimeter of the triangle? Round the answer to the nea

rest hundredth.
Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0
16.24 because at the end when you add the ast three square roots you need to add that's what you get,.
marin [14]3 years ago
4 0
The perimeter is 16.2. Let me know if you need me to show you how I got this 
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PLEASE HELP ME!!!!! A quadrilateral with vertices (0,0), (4,0), (3,2), (1,1) is mapped to a quadrilateral with vertices (6,3).(-
Murljashka [212]

Answer:

( 2,1) is the center of dilation and -2 is the scale factor

Step-by-step explanation:

We can use the formula

A' = k( x-a) +a, k( y-b)+b  where ( a,b) is the center of dilation and k is the scale factor

(0,0) becomes (6,3)

( 6,3) =  k( 0-a) +a, k( 0-b)+b

6 = -ka+a

3 = -kb+b

We also have

(4,0) becomes (-2,3)

( -2,3) =  k( 4-a) +a, k( 0-b)+b

-2 =4k -ka+a

3 = -kb+b

Using these two equations

6 = -ka+a

-2 =4k -ka+a

Subtracting the top from the bottom

-2 =4k -ka+a

-6 = ka -a

-------------------

-8 = 4k

Divide by 4

-8/4 = 4k/4

-2 = k

Now solving for a

6 = -ka +a

6 = - (-2)a +a

6 = 2a+a

6 = 3a

Divide by 3

6/3 =3a/3

2=a

Now finding b

3 = -kb+b

3 = -(-2)b+b

3 = 2b+b

3 = 3b

b=1

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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