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2 years ago

10

A triangle has vertices (-1,2), (3,1), and (7,2). What is the approximate perimeter of the triangle? Round the answer to the nea

rest hundredth.

2 answers:

Vedmedyk [2.9K]2 years ago

6 0

16.24 because at the end when you add the ast three square roots you need to add that's what you get,.

marin [14]2 years ago

4 0

The perimeter is 16.2. Let me know if you need me to show you how I got this

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denpristay [2]

Answer:

ABWJRIRISBDBDBHSHS

Step-by-step explanation:

Hatdog HWHWHWHSHSHSQIWIW

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2 years ago

Please Help Me!!!!!!!

RSB [31]

Cannot be determined is the answer.

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2 years ago

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Please help!!! I need this done today!!

Kryger [21]

Answer:

1) distance travelled = 75mi

time taken = 3 hrs.

speed = distance/time

= 75/3 = 25 mi/hr.

now, if time = 1.6 hrs.

Distance = speed x time

= 25 x 1.6 = 40.0 mi

---------------------------------------------------------------------------------------------

2) earning for 8 hrs. of work = $120.

therefore, rate of earning per hr. = 120/8 = $15/hr.

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3 years ago

Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector

Feliz [49]

$f(x,y,z)=2z^2x+y^3$

$f$ has gradient

$\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k$

which at the point (-1, 4, 3) has a value of

$\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k$

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say $\vec u=15\,\vec\imath+25\,\vec\jmath$ , in which case we have

$\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}$

Then the derivative of $f$ at (-1, 4, 3) in the direction of $\vec u$ is

$D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}$

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3 years ago

A) 0,2 x 5/7 + 11/14 = ?

NemiM [27]

I hope this helps you

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3 years ago

Read 2 more answers