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4 years ago

13

There are blue, red and yellow marbles in a bag. The probability of choosing a blue marble is 1/8, and the probability of choosi

ng a red marble is 1/2. What is the probability of choosing a yellow marble?
Please explain

1 answer:

Irina18 [472]4 years ago

3 0

Answer: I think it's 9/10

Step-by-step explanation:

If im worng im soooo sry

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Divide 33 photos into two groups so that the ratio is 4 to 7

Andre45 [30]

Total ratio = 4+7 = 11
33/11 = 3
4x3 = 12
7x3 = 21
so the two groups are 12:21
which is also = 4:7

3 0

3 years ago

If B = {−13, −9, −7, −3}, choose the set A that will make the following statement false.

Svetach [21]

Answer: c.A is the set of rational numbers

Step-by-step explanation:

B ⊆ A means that every element of B is an element of A

B = { -13 , -9 , -7 , - 3 }

The element of B are negative integers , this mean that the element of A must also be integers therefore :

Option a is correct.

Option b is also correct

Rational numbers are numbers that can be express in the form a/b , examples are : 1/2 , 3/ 4 , 5/6 ...

clearly , this does not necessarily define A , so option c is the odd one out

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4 years ago

In ΔTUV, v = 990 inches, t = 840 inches and ∠U=148°. Find the length of u, to the nearest inch.

Scilla [17]

Answer:

the answer is 1760

Step-by-step explanation:

5 0

3 years ago

Function rule and y intercept

stiks02 [169]

to get the equation for any straight line, all we need is two points from it, so hmmm say from this table let's use (2,0) and (6,-8)

$\bf \begin{array}{|r|r|r|r|r|r|} \cline{1-6} days&x&2&4&6&8\\ \cline{1-6} dollars&y&0&-4&-8&-12\\ \cline{1-6} \end{array}~\hfill (\stackrel{x_1}{2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-8}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{-8}{4}\implies \cfrac{\stackrel{rise}{-2}}{\underset{run}{1}}\implies \stackrel{slope}{-2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-2}(x-\stackrel{x_1}{2}) \\\\\\ \stackrel{~\hfill y-intercept}{y=-2x\stackrel{\downarrow }{+4}}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

6 0

4 years ago

Which is the equation of Line B?

notka56 [123]

Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept
Slope Formula: $\frac{y_2-y_1}{x_2-x_1}$

So firstly, to find the slope of this equation, plug the two points, (1,1) and (-3,2), into the slope formula and solve as such:

$\frac{1-2}{1-(-3)}=-\frac{1}{4}$

Next, plug either one of the points into the x and y coordinates to solve for b as such:

$2=-\frac{1}{4}*-3+b\\2=\frac{3}{4}+b\\\frac{5}{4}=b$

<u>Our final equation is $y=-\frac{1}{4}x+\frac{5}{4}$ , or the third option.</u>

8 0

3 years ago