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Scorpion4ik [409]
3 years ago
11

rhombus has sides of length 10 cm. and the angle between two adjacent sides is 76 degrees. Find the lengths of the other diagona

l.
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0
Let the length of one of the diagonals be 2x and the other be 2y, then
cos (76/2) = x/10
x = 10 cos 38 = 7.88 cm

sin (76/2) = y/10
y = 10 sin 38 = 6.16 cm
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What is the probability that a randomly selected person supports the new station??
mezya [45]

Answer:

.52

Step-by-step explanation:

We can write an equation

supports/all

we can see that 27 males and 25 females support which means that

27+25= 52 total people support

now we just need to find the number of people surveyed

we do this by summing everything

27+25+18+13+5+12=100

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4 0
3 years ago
Read 2 more answers
Which expression is equivalent to 45 divided by (2 - x)
makvit [3.9K]

Answer:

 45

---------

(2 - x)

Step-by-step explanation:

That would be:

 45

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(2 - x)

Also valid:  45/(2 - x)

6 0
2 years ago
I'm still stuck on this one
Evgesh-ka [11]
The answer would be -4.5/5. You would have to plot the number in between -2 and - 1 4/5. Hope this helps!
7 0
3 years ago
Olivia ordered 24 cupcakes and a layer of cake. The layer cost $16 and the total cost of the order was $52. What was the price o
ArbitrLikvidat [17]
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4 0
3 years ago
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Find the distance between (3,-3) and (2,7)
yarga [219]

Answer:

\sqrt{101} = D

Step-by-step explanation:

Method #1

We can draw a <em>right triangle</em> on the graph upon where the points are located and use the Pythagorean Theorem:

{a}^{2} + {b}^{2} = {c}^{2}

{1}^{2} + {10}^{2} = {c}^{2}

1 + 100 = {c}^{2}

101 = {c}^{2}

\sqrt{101} = c

* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.

_______________________________________________

Method #2

Or, we can use the Distance Formula:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

[2, 7] [3, −3]

\sqrt{[-3 + 2]^{2} + [3 + 7]^{2}} = D

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\sqrt{1 + 100} = D

\sqrt{101} = D

** You see? It does not matter which method you choose, as long as you are doing the work correctly.

I am delighted to assist you anytime.

5 0
3 years ago
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