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Natali [406]
2 years ago
5

Tan^2 70° -sec^2 70°​

Mathematics
1 answer:
kipiarov [429]2 years ago
4 0

Answer:

-1

Step-by-step explanation:

We need to find the value of tan² 70° -sec² 70°​.

We know that,

\sec^2\theta-\tan^2\theta=1 ...(1)

We can write the given expression as :

tan² 70° -sec² 70° = -(-tan² 70° +sec² 70°)

=-(sec² 70°-tan² 70°)

Using identity (1)

=-(1)

= -1

Hence, the value of the given expression is -1.

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ira [324]

A given<u> shape</u> that is <em>bounded</em> by three <u>sides</u> and has got three <em>internal angles</em> is referred to as a <u>triangle</u>. Thus the <em>value</em> of <u>PB</u> is 8.0 units.

A given <em>shape</em> that is <u>bounded</u> by three<em> sides</em> and has got three <em>internal angles</em> is referred to as a <u>triangl</u>e. Types of <u>triangles</u> include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The sum of the<em> internal angles</em> of any <u>triangle</u> is 180^{o}.

In the given question, point<u> P</u> is <u>center</u> of the given <u>triangle</u> such that <APB = <APC = <BPC = 120^{o}. Such that <u>line</u> PB <em>bisects</em> <ABC into two <u>equal</u> measures of 30^{o}.

Thus;

<ABP = 30^{o}

Thus,

<ABP + <APB + <BAP = 180^{o}

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<BAP = 180^{o} - 150

<BAP = 30^{o}

Apply the <em>Sine rule</em> to determine the value of PB, such that;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{8}{Sin 30} = \frac{PB}{Sin 30}

BP = \frac{8*Sin 30}{Sin 30}

    = 8

BP = 8.0

Therefore, the value of <u>PB</u> = 8 units.

For more clarifications on Sine rule, visit: brainly.com/question/27174058

#SPJ1

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Option C.
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