Question

Write an equation of the circle with center (2,-3) and radius 8.

Answer 1

Answer:

$(x-2)^2+(y-3)^2=64$

You may simplify further

Step-by-step explanation:

The eqn. of a circle with centre (h,k) and radius r is given by,

$(x-h)^2+(y-k)^2=r^2\\(x-2)^2+(y-3)^2=8^2\\(x-2)^2+(y-3)^2=64$

Answer 2

Answer:

(x-2)^2+ (y+3)^2 = 64

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2+ (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x-2)^2+ (y- -3)^2 = 8^2

(x-2)^2+ (y+3)^2 = 8^2

(x-2)^2+ (y+3)^2 = 64