Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
Answer: the dogs skin cells contain cell walls<span>
When comparing the skin cells from a dog to bacterial cells, which observation would be false?</span>
Answer:
<u>
They have hydrophilic heads and hydrophobic tails.</u>
Explanation:
Phospholipid membranes are comprised of a chain of lipids. These typically are arranged in a bilayer; the hydrophilic lipid heads are polar, and face outwards, while the hydrophobic tails are polar facing inwards.
The membranes are selectively permeable, and only allow the movement of small, non-polar molecules through the bilayer.
Answer:
telophase is the correct answer
Explanation:
sorry if its incorrect.
Answer: Biotic means a living factor in the environment. The opposite would be abiotic, which is a non-living factor like light, pH, wind, etc.
Explanation:
