Question

When nickel metal is added to silver nitrate in solution, silver metal and nickel (II) nitrate are

Answer 1

Answer:

Mass of silver metal = 424 g

Explanation:

Data Given

Reactants = Nickle (Ni) metal and Silver nitrate (AgNO₃)

product = Ni(NO₃)₂ and Silver metal (Ag)

mass of nickle = 115 g

mass of silver = ?

Solution:

First write a balanced reaction

               Ni + 2AgNO₃ ----------> 2Ag + Ni(NO₃)₂

Now Look for the  number of moles of Nickle and Silver meta

                Ni + 2AgNO₃ ----------> 2Ag + Ni(NO₃)₂

               1 mol                              2 mol

So,

1 mole of nickle combine with silver nitrate and produce 2 moles of silver metal

Now Convert moles to mass for which we have to molar masses of Nickle and Silver metal

Molar mass of Nickle = 58.6 g/mol

Molar mass of Silver = 108 g/mol

                 Ni         +     2AgNO₃   ---------->    2Ag      +     Ni(NO₃)₂

               1 mol (58.6 g/mol)                      2 mol (108 g/mol)

                58.6 g                                                216 g

So,

58.6 g of Nickle metal produces 216 grams of silver metal.

Now

What mass of silver is produced from 115 g of Ni

Apply unity formula

                       58.6 g of Ni ≅ 216 g of Ag

                       115 g of Ni ≅ X g of Ag

By doing cross multiplication

                     Mass of Ag = 216 g x 115 g / 58.6 g

                     Mass of Ag = 424 g