Explanation:
The reaction is as follows.
Standard values of bond energies are as follows.
C-C = 347 kJ/mol
C-H = 414 kJ/mol
C-O = 360 kJ/mol
O-H = 464 kJ/mol
O=O = 498 kJ/mol
C=O = 799 kJ/mol
Hence, calculate the change in enthalpy of the reaction as follows.
= [5(C-H) + 1(C-C) + 1(C-O) + 1(O-H) + 3(O=O)] - [4(C=O) + 6(O-H)]
=
= (4735 - 5980) kJ
= -1245 kJ
Thus, we can conclude that the enthalpy of given reaction is -1245 kJ.
Answer:
The volume of 55 grams of BF₃ is 18.1664 L.
Explanation:
If the molar mass of compound BF₃ is 67.81 , then the number of moles 55 grams of compound contains is calculated as:
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Then it is possible to apply the following rule of three: if by definition of STP 1 mole of a compound occupies 22.4 L, 0.811 moles of the compound occupies how much volume?
volume= 18.1664 L
<u><em>The volume of 55 grams of BF₃ is 18.1664 L.</em></u>
Answer:
B
Explanation:
Noble gases are in group 18 (neon, argon, etc)
Answer:
Explanation:
When you heat ice, its temperature rises, but as soon as the ice starts to melt, the temperature stays constant until all the ice has melted. This happens because all the heat energy goes into breaking the bonds of the ice's crystal lattice structure. :)