Answer: metals loss their valence electron during bonding to form a compound
Explanation:
Answer:
The answer to your question is m = 1.6
Explanation:
Data
mass of NaCl = 111 g
volume of water = 1.2 L
Molality = ?
Formula
Molality = number of moles / volume (L)
Process
1.- Calculate the moles of NaCl
Molecular mass = 23 + 35.5 = 58.5 g
1 mol of ------------------- 58.5 g
x -------------------- 111 g
x = (111 x 1) / 58.5
x = 1.897 moles of NaCl
2.- Calculate the mass of water
density of water = 997 kg/m³
mass = volume x density
mass = 0.0012 x 997
mass = 1.19 kg
3.- Calculate molality
m = 1.897/1.19
m = 1.6
<span>1. 5.6 L of NO2(g)
2. 7.5 L of H2(g)
3. 11.2 L of N2(g)
4. 22.4 L of CO(g)</span>
Answer:
Mg and Cl
Explanation:
The magnesium would lose two electrons, becoming +2 charged and two chlorines (not one) would each gain one electron, each becoming -1 charged in the process.
The three ions would adhere (bond) to each other by the positive/negative attraction between the ions.
Answer:
Equilibrium will shift leftwards towards NO2.
Explanation:
Hello there!
In this case, according to the Le Cha telier's principle, it is possible to realize that the increase of the volume turns out in the shift towards the most of the gaseous moles are in; in such a way, for the given chemical reaction, we can notice how NO2 (reactant side) has the most of the moles (2 moles in comparison to 1 mole of N2O4); and therefore, by increasing the volume, the equilibrium will shift to it, it means leftwards.
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