Answer:
8.1433 g of XeF₆ are required.
Explanation:
Balanced chemical equation;
XeF₆ (s) + 3H₂ (g) → Xe (g) + 6HF (g)
Given data:
Volume of hydrogen = 0.579 L
Pressure = 4.46 atm
Temperature = 45 °C (45+273= 318 k)
Solution:
First of all we will calculate the moles of hydrogen
PV = nRT
n = PV/ RT
n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K
n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹
n = 0.0995 mol
Mass of hydrogen:
Mass = moles × molar mass
Mass = 0.0995 mol × 2.016 g/mol
Mass = 0.2006 g
Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.
H₂ : XeF₆
3 : 1
0.0995 : 1/3× 0.0995 = 0.0332 mol
Now we will calculate the mass of XeF₆.
Mass = moles × molar mass
Mass = 0.0332 mol × 245.28 g/mol
Mass = 8.1433 g
