Answer:
(x-3) years
Step-by-step explanation:
We are given that
Age of Jonathan= x years
Sage is 7 years older than Jonathan
It means
Age of Sage=(x+7) years
We have to find the age of Sage 10 years ago.
10 Years ago,
Age of Jonathan=(x-10) years
Age of Sage=(x+7-10) years
Age of Sage=(x-3) years
Hence, 10 years ago, age of Sage =(x-3) years
A squared + B squared = C squared
Answer:
min = 64.2m ; max = 86.2m
Step-by-step explanation:
Complete question :
A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The population would grow by 30 percent per year
how many after one year
how many after two years
Answer:
39 deers
51 deers
Step-by-step explanation:
The question can be expressed using the compounding rate formula:
A = P(1+r)^t
A = final population ; P = initial population ; rate, r = 30% = 0.3 ; t = time
After 1 year, t = 1
A = 30(1 + 0.3)^1
A = 30(1.3)^1
A = 39 deers
B.)
After 1 year, t = 2
A = 30(1 + 0.3)^2
A = 30(1.3)^2
A = 50.7
A = 51 deers approximately
