The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4
Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1
Thirty six divided by four is equal to nine
Answer:
286cm²
Step-by-step explanation:
Let the parallel sides be 12cm and 10cm
Height h = 26cm
Area of a trapezium = 1/2(a+b) * h
Area of a trapezium = 1/2(12+10)* 26
Area of a trapezium = 1/2(22)*26
Area of a trapezium = 11 * 26
Area of a trapezium = 286cm²
Hence the area of the tiles is 286cm²
First you chang top fractions into decimal add and divide that by 4 which is equal to 0.375 hope it helps.
Answer:
Then the total area is 116 cm^2 which agrees with answer D
Step-by-step explanation:
Notice we need to calculate the area of two rectangles (one larger at the bottom and a smaller one on top)
The Area of a rectangle is the product: base x height
In our case :
Area of Big rectangle = 12 cm x 7 cm = 84 cm^2
Area of smaller rectangle = 8 cm x 4 cm = 32 cm^2
Then the total area is: 84 cm^2 + 32 cm^2 = 116 cm^2
