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Hoochie [10]
4 years ago
11

Define length, mass and volume in you own words

Chemistry
1 answer:
Vlad1618 [11]4 years ago
5 0
Volume is the amount of space an object takes up . mass is the measure of the amount of matter an object contains . and length is the distance from one point to another.
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Can some one help me in this I hope this will be easy for you :)
kramer

Answer:

c) i)  Mg²⁺   ii) O²⁻

Explanation:

I don't know the answer to Q7. because you don't show the diagram

5 0
3 years ago
What is the name of MnO? Explain how you determined the bond type and the steps you used to determine the naming convention for
xeze [42]

Answer:

Magnesiumoxide

Explanation:

I don't know

5 0
3 years ago
The temperature of a sample of gas in a steel
Snezhnost [94]

Answer:

P_2=51.7kPa

Explanation:

Hello,

In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior via a directly proportional relationship:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Thus, since we are asked to compute the final pressure we solve for it in the previous formula, considering the temperature in absolute Kelvin units:

P_2=\frac{P_1T_2}{T_1}=\frac{30.0kPa*(25.0+273)K}{(-100.0+273)K} \\\\P_2=51.7kPa

Best regards.

3 0
3 years ago
Read 2 more answers
Which law is used to determined the relationship between the volume and the number of moles
alukav5142 [94]

Answer:

Avogadro's Law

Explanation:

Avogadro's number (6.23 x 10^23)

Avogadro's law states that the volume and number of moles are proportional if pressure and temp remain constant.

8 0
4 years ago
Read 2 more answers
How many moles are equal to 12.65 grams of Al2(SO4)3?
____ [38]

Answer:

0.03697 mol Al₂(SO₄)₃

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

12.65 g Al₂(SO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Al - 26.98 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol

<u>Step 3: Convert</u>

<u />12.65 \ g \ Al_2(SO_4)_3(\frac{1 \ mol \ Al_2(SO_4)_3}{342.17 \ g \ Al_2(SO_4)_3} ) = 0.03697 mol Al₂(SO₄)₃

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

We already have 4 sig figs in the final answer, so no need to round.

5 0
3 years ago
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