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2 years ago

How many atoms are there in 15.0 grams of Sulfur (S)?

Chemistry

1 answer:

aev [14]2 years ago

6 0

Answer:

Explanation:

Mol x Avogadro's number

Mol : mass / molar mass

Avogadro's no: 6.02E+23

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The decomposition of nitrogen dioxide is described by the following chemical equation:

kow [346]

Answer:

The balanced chemical equation will be " $NO_{2}+O\rightarrow NO+O_{2}$ ".

Explanation:

The given equation is:

$2NO_{2}\rightarrow 2NO+O_{2}$

Step 1:

$2NO_{2}\rightarrow NO+O$ ...(equation 1)

Step 2:

$NO_{2}+O\rightarrow NO+O_{2}$ ...(equation 2)

On adding "equation 1" and "equation 2", we get

⇒ $NO_{2}+NO_{2}+O\rightarrow NO+O+NO+O_{2}$

⇒ $2NO_{2}\rightarrow 2NO+O_{2}$

The second step:

⇒ $NO_{2}+O\rightarrow NO+O_{2}$

3 0

3 years ago

What kind of group 1 atoms are the most reactive? a. Small atoms c. Atoms with the most electrons in the valence level b. Large

garri49 [273]

Answer:

large atoms

Explanation:

its kinda obvious

4 0

2 years ago

Read 2 more answers

You place a balloon in a closed chamber at STP. When the balloon doubles in size, what happens to the chamber pressure? A.) The

larisa86 [58]

If you increase the volume the pressure will decrease. so the best answer is C

4 0

3 years ago

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Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

3 years ago

What type of reaction is shown in the following chemical equation in NH3+HC1 NH4C1

natulia [17]

Explanation:

combination reaction

3 0

2 years ago

Read 2 more answers