When you understand the etymologies of scientific terms, they make a lot of sense in relation to the term. The etymologies themselves often serve as a reasonably okay definition for the term.
Here's an example, many scientific terms have Greek or Latin etymologies. Take "archaeology" (for an example) Etymologically, it consists of two Greek words "archaeo" (old, ancient) and "logos" (a word, discourse, or study). Therefore, etymologically "archaeology" means "the study of old/ancient things."
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Answer:
Mass of H₂O is 3.0g
Explanation:
The reaction equation is given as:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
Parameters that are known:
Mass of CO₂ used = 7.3g
Unknown: mass of water consumed = ?
Solution
To solve this kind of problem, we simply apply some mole concept relationships.
- First, we work from the known to the unknown. From the problem, we have 7.3g of CO₂ that was used. We can find the number of moles from this value using the expression below:
Number of moles of CO₂ = 
- From this number of moles of CO₂, we can use the balanced equation to relate the number of moles of CO₂ to that of H₂O:
6 moles of CO₂ reacted with 6 moles of H₂O(1:1)
- We can then use the mole relationship with mass to find the unknown.
Workings
>>>> Number of moles of CO₂ =?
Molar mass of CO₂ :
Atomic mass of C = 12g
Atomic mass of O = 16g
Molar mass of CO₂ = 12 + (2 x16) = 44gmol⁻¹
Number of moles of CO₂ =
= 0.166moles
>>>>>> if 6 moles of CO₂ reacted with 6 moles of H₂O, then 0.166moles of CO₂ would produce 0.166moles of H₂O
>>>>>> Mass of water consumed = number of mole of H₂O x molar mass
Mass of H₂0 = 0.166 x ?
Molar mass of H₂O:
Atomic mass of H = 1g
Atomic mass of O = 16
Molar mass of H₂O = (2x1) + 16 = 18gmol⁻¹
Mass of H₂O = 0.166 x 18 = 3.0g
Answer:
0.64 g of S
Solution:
The balance chemical equation is as follow,
2 Cu + S ----> Cu₂S
According to equation,
127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S
So,
2.54 g Cu will produce = X g of Cu₂S
Solving for X,
X = (2.54 g * 159 g) / 127 g
X = 3.18 g of Cu₂S
Now, it is confirmed that the reaction is 100% ideal. Therefore,
As,
127 g (2 mole) Cu required = 32 g (1 mole) of S
So,
2.54 g Cu will require = X g of S
Solving for X,
X = (2.54 g * 32 g) / 127 g
X = 0.64 g of S
The percent yield : 4. 84.58%
<h3>Further explanation</h3>
Reaction
CaCO₃ ⇄ CaO+CO₂
mass CaCO₃ = 2.3 × 10³ g
mol CaCO₃ (MW=100.0869 g/mol) :

From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98
mass CaO(MW=56.0774 g/mol)⇒ (theoretical) :

The percent yield :

Answer:
1.) 9 carbon atoms, only
Explanation:
Prefix: non- simply means 9.
Suffix: -ene means double bond, -yne means triple bond, and -ane means single bonded carbons.