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3 years ago

How many moles would be in 85.OmL of 0.750M KOH?

Chemistry

1 answer:

Harlamova29_29 [7]3 years ago

7 0

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity = 0.750 M

It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

$Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol$

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

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