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swat32
3 years ago
9

Explain the strategy you used to solve 287 divided into 41

Mathematics
1 answer:
Verdich [7]3 years ago
5 0
The answer is 7. I got this by putting the problem into an equation.287/41 when you do this you can then find how many times 41 go into 287 which is 7.
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Is this correct??<br>I don't know
Alexandra [31]
In my opinion, ur right
4 0
3 years ago
How many sets of four consecutive positive integers are there such that the product of the four integers is less than $100,\!000
SVEN [57.7K]

Answer:

16,17,18,19

Step-by-step explanation:

one guy guessed. probably using a calculator

another guy took the 4th root of 100,000 and rounded down a number

(a third way started like this

n*(n+1)*(n+2)(n+3)=100000

4 0
3 years ago
A number cube with six sides numbered 1 through 6 is rolled. the probability of rolling a 5 is 16 . what is the probability of n
egoroff_w [7]
1/6 hope this helps you give a brainliest please thank you.
6 0
4 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0
3 years ago
1.The growth of a sample of bacteria can be modeled by the function b(t)=100(1.06)t where b is the number of bacteria and t is t
qwelly [4]

Given:

The growth of a sample of bacteria can be modeled by the function

b(t)=100(1.06)^t

where, b is the number of bacteria and t is time in hours.

To find:

The number of total bacteria after 3 hours.

Solution:

We have,

b(t)=100(1.06)^t

Here, b(t) number of total bacteria after t hours.

Substitute t=3 in the given function, to find the number of total bacteria after 3 hours.

b(t)=100(1.06)^3

b(t)=100(1.191016)

b(t)=119.1016&#10;

Therefore, the number of total bacteria after 3 hours is 119.1016.

4 0
3 years ago
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