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GREYUIT [131]
3 years ago
11

Circle O has tangent AB and secant AC as shown. arc BC measures 4x+2-. arc BE measures 2x-10. What is the measure of arc CB

Mathematics
1 answer:
dangina [55]3 years ago
7 0

Answer:

b. 160°

Step-by-step explanation:

angle A = (far arc - near arc)/2

far arc is  arc BC and near arc is arc BE. Replacing into the equation:

∠A = (arc BC - arc BE)/2

50 = [4x + 20 - (2x - 10)]/2

50*2 = 2x + 30

x = (100 - 30)/2

x = 35°

Replacing this information into arc BC equation:

arc BC = 4(35) + 20 = 160°

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Step-by-step explanation:

A = -7.

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3 years ago
6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the
MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

a_1 the horizontal distance between the first observer and the ballonist

a_2 the horizontal distance between the second observer and the ballonist

\alpha _1 and \alpha _2 the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

S=S_1+S_2 (equation 2)

S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}

And for S_2 will be the same:

S_2=\frac{h^{2} }{\tan(\alpha _2)}

Replacing in the equation 2:

S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}

So, we can replace all the known data in the last equation:

h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0
3 years ago
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iVinArrow [24]

Answer:

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Step-by-step explanation:

i had the same question for school

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Answer:

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When they made the first clock how they know what time it was to set it to?
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They probably looked at the sun and it’s shadows
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