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VARVARA [1.3K]
3 years ago
14

Seth purchased a printer for 350 the price of the printer that jose purchased was 4/5 the price that seth paid How much did hose

pay for his printer
Mathematics
1 answer:
grigory [225]3 years ago
8 0

Jose paid $280 for the printer since that is 4/5 of 350

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Find the area of this circle please…Use 3 for pi
ZanzabumX [31]

Given:

The radius of circle is 11 inch

The value for pi is 3

The objective is to find the area of the circle.

The area of the circle is given by the formula:

A=\pi\times r^2^{}

Substituting ,r = 11

\pi=3

We get:

\begin{gathered} A=\pi\times r^2 \\ =3\times(11)^2 \\ =3\times121 \\ =363 \end{gathered}

Hence, the area of the circle is 363 square inches

5 0
1 year ago
In the diagram below AC is perpendicular to BD find x show all work
ozzi
3x + 9 = 90
3x = 90 - 9 = 81
x = 81/3 = 27
x = 27
7 0
3 years ago
Read 2 more answers
Pls help will give brainliest answer and 5star
Ipatiy [6.2K]

1. Which polygon or polygons are regular?

A regular polygon is a polygon that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length).

Therefore your answer is:

A. equilateral triangle

C. square


2. Which polygon is always irregular?

traingle - NOT (equilateral triangle)

trapezoid - YES

square - NOT

hexagon - NOT (regular hexagon)

6 0
3 years ago
Look at the figure above. The surface area is _____ square cm.
user100 [1]

Answer: 252

Step-by-step explanation:

6 0
3 years ago
The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) =
Dafna1 [17]

Answer:

a) L'(t) = 34.416*e^(-0.18*t)

b) L'(0) = 34 cm/yr , L'(1) =29 cm/yr , L'(6) =12 cm/yr

c) t = 10 year                                          

Step-by-step explanation:

Given:

- The length of fish grows with time. It is modeled by the relation:

                                   L(t) = 200*(1-0.956*e^(-0.18*t))

Where,

L: Is length in centimeter of a fist

t: Is the age of the fish in years.

Find:

(a) Find the rate of change of the length as a function of time

(b) In this part, give you answer to the nearest unit. At what rate is the fish growing at age: t = 0 , t = 1, t = 6

c) When will the fish be growing at a rate of 6 cm/yr? (nearest unit)

Solution:

- The rate of change of length of a fish as it ages each year  can be evaluated by taking a derivative of the Length L(t) function with respect to x. As follows:

                             dL(t)/dt = d(200*(1-0.956*e^(-0.18*t))) / dt

                             dL(t)/dt = 34.416*e^(-0.18*t)

- Then use the above relation to compute:

                            L'(t) = 34.416*e^(-0.18*t)

                            L'(0) = 34.416*e^(-0.18*0) = 34 cm/yr

                            L'(1) = 34.416*e^(-0.18*1) = 29 cm/yr

                            L'(6) = 34.416*e^(-0.18*6) = 12 cm/yr

- Next, again use the derived L'(t) to determine the year when fish is growing at a rate of 6 cm/yr:

                             6 cm/yr = 34.416*e^(-0.18*t)

                             e^(0.18*t) = 34.416 / 6

                             0.18*t = Ln(34.416/6)

                             t = Ln(34.416/6) / 0.18

                             t = 10 year

7 0
3 years ago
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