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Advocard [28]
3 years ago
5

Equivalent Fractions

Mathematics
1 answer:
Maru [420]3 years ago
6 0

C is the correct answer


3/5 x 2 =6/10


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A sample space consists of 80 separate events that are equally likely. What is the probability of each? A sample space consists
yuradex [85]

Answer:

1/80

Step-by-step explanation:

7 0
2 years ago
Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has
Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0),  Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8  

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

6 0
3 years ago
1<br>Prove that<br>1: sin/1-cot + cos/1-tan=cos+sin​
Anit [1.1K]

Answer:

have:

\frac{sin}{1-cot}+\frac{cos}{1-tan}\\\\=\frac{sin}{1-\frac{cos}{sin} }+\frac{cos}{1-\frac{sin}{cos} }\\\\=\frac{sin^{2} }{sin-cos}+\frac{cos^{2} }{cos-sin} \\\\=\frac{sin^{2} }{sin-cos}-\frac{cos^{2} }{cos-sin}\\\\=\frac{sin^{2}-cos^{2}  }{sin - cos}\\\\=\frac{(sin-cos)(sin+cos)}{sin-cos}\\\\=sin+cos

Step-by-step explanation:

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3 years ago
Martina chose a random sample of 10 bags of candy from two different Brands, A and B. All bags in the sample are the same size.
Alborosie
I found the dot plots that accompanies this problem.

Based on the plots, the <span>statement that gives is a valid comparison of the number of candies in the bags of the two Brands is:

</span><span>B. The number of candies in the bags from Brand B is greater and less consistent than the number of candies in the bags from Brand A.

Dots in Brand B are scattered and whereas dots in Brand A are not and they are more concentrated between 52 to 55 range. </span>

7 0
2 years ago
If 11 key chains cost $53.35 than 4 key chains cost $
xeze [42]

53.35/11 = 4.85 for 1 key chain

4.85 *4 = 19.40


8 0
2 years ago
Read 2 more answers
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