the mass of one California condors is 9 kilograms. what is the mass of twelve 9-kilogram California condors?

Use the five number summary calculated in part C to create a box plot representing the data. Draw a box plot representing the fo

Alex777 [14]

Answer: Minimum: 20

Quartile Q1: 23.5

Median: 27

Quartile Q3: 31

Maximum: 35

Step-by-step explanation: The five number summary gives you a rough idea about what your data set looks like. For example, you’ll have your lowest value (the minimum) and the highest value (the maximum) or where data is more concentraced. The main reason you’ll want to find a five-number summary is to find more useful statistics, like the interquartile range IQR, sometimes called the middle fifty.

7 0

3 years ago

Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 20 feet,

Harman [31]

First, let's list the lengths of the sides in descending order.

Lengths of sides of quadrilateral ABCD: 20, 18, 14, a

Lengths of sides of quadrilateral EFGH: b, c, 6, 5

From the listings above, we see that he sides measuring 14 and 6 are corresponding.

We are looking for c which corresponds to 18.

14 is to 6 is as 18 is to c

14/6 = 18/c

7/3 = 18/c

7c = 3 * 18

7c = 54

c = 54/7 = 7 5/7

Answer: 7 5/7 feet

5 0

3 years ago

Read 2 more answers

1. A heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. of these seeds, 110 pro

garri49 [273]

Answer:

Part 1 , not significant

Part II, significant

Step-by-step explanation:

Given that a heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. of these seeds, 110 produce white-fruited plants while only 90 produce yellow-fruited plants

$H_0: Both colours are equally likely\\H_a: Both colours are not equally likely$

(Two tailed chi square test)

We assume H0 to be true and find out expected

If H0 is true expected would be 100 white and 100 yellow

Chi square = $\Sigma \frac{(O-E)^2}{E} \\=\frac{(110-100)^2}{100} +frac{(90-100)^2}{100} \\=2$

df = 1

p value = 0.152799

Since p value > 0.05 at 5% level we accept that the colours are equally likely

2)

Here observed are 1100 and 900

Expected 1000 & 1000

df = 1

Chi square = $\frac{20000}{100} =200$

p value <0.0001

These results are here statistically significant.

8 0

3 years ago

There are approximately 39.37 iches in 1 meter. how many meters are in 170 inches

mel-nik [20]

170 divided by 39.37= 4.32 meter

6 0

3 years ago

Dropping less than two inches per mile after emerging from the mountains, a river drains into the ocean. One day's discharge a

forsale [732]

Answer:

4000 gallons.

Step-by-step explanation:

One day's discharge at the mouth of the river is 2 trillion gallons and it can supply all of country A's households for five months.

Now, if there are 100 million households in country A.

Then, the amount of water an average household uses each month will be given by

$\frac{2 \times 10^{12} }{100 \times 10^{6} \times 5} = 4000$ gallons. (Answer)

6 0

3 years ago