All categories

3 years ago

What would my final balance be if i put R650 in the bank for 60 Months with an interest rate of 6%

1 answer:

7 0

60 months is 5 years
12 × 5 = 60

Interest = Principle amount × Rate × Time in years
= 650 × 0.06 × 5 (6% = $\frac{6}{100}$ = 0.06)
= R195

R650 + R195 = R845

You might be interested in

If two zeroes of a polynomial x3+5x2+7x+3 are -1 and-3 then find the third Zero

belka [17]

Answer:

Third zero is -1.

Step-by-step explanation:

consider the given polynomial is

$P(x)=x^3+5x^2+7x+3$

It is given that -1 and -3 are two zeroes, therefore (x+1) and (x+3) are two factors of given polynomial.

The given polynomial can be rewritten as

$P(x)=x^3+x^2+4x^2+4x+3x+3$

$P(x)=x^2(x+1)+4x(x+1)+3(x+1)$

$P(x)=(x+1)(x^2+4x+3)$

Now, splitting the middle term, we get

$P(x)=(x+1)(x^2+3x+x+3)$

$P(x)=(x+1)(x(x+3)+1(x+3))$

$P(x)=(x+1)(x+1)(x+3)$

$P(x)=(x+1)^2(x+3)$

Here, power of (x+1) is 2. It means the multiplicity of zero -1 is 2.

So, three zeroes are -1, -1 and -3.

Therefore the third zero is -1.

7 0

3 years ago

Factor completely 3x2 + x + 7.

OlgaM077 [116]

It should be prime :DDD

6 0

3 years ago

Read 2 more answers

What are the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of

Mrrafil [7]

Answer:

$\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )$

Step-by-step explanation:

Given: P is Three-fifths the length of the line segment from K to J

To find: x- and y-coordinates of point P on the directed line segment from K to J

Solution:

Section formula:

Let point K and J be $(x_1,y_1)\,,\,(x_2,y_2)$ such that the point $p(x,y)$ divides KJ in ratio $m:n$

Then coordinates of point P are given by $\left ( \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n} \right )$

Take $m:n=3:5$

So,

coordinates of point P = $\left ( \frac{3x_2+5x_1}{3+5},\frac{3y_2+5y_1}{3+5} \right )=\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )$

7 0

3 years ago

Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet

Mumz [18]

Answer:

$296.693\leq x\leq 319.307$

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

$x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }$

Where x' is the sample mean, s is the population standard deviation, n is the sample size and $z_{\alpha /2}$ is the z-score that let a proportion of $\alpha /2$ on the right tail.