45 and 46 pls thx and I need work too

Heres yo go mattty lolololololol

gladu [14]

Answer:

x = 16

Step-by-step explanation:

71 - 15 = 56

56 ÷ 14 = 4

$\sqrt{16}$ = 4

Check work:

$\sqrt{16}$ = 4

14 x 4 = 56

56 + 15 = 71

7 0

2 years ago

Find the product of 0.056 and 0.73. 0.04088 0.4088 0.0056

IrinaK [193]

0.04088 0.056 ×0.73 =0.04088

4 0

3 years ago

6) There are many cylinders with a height of 4 inches.

diamong [38]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

height of cylinder h = 4 inches

Given the table

Radius Volume

1 ___

2 ___

3 ___

Determining the Volume of the cylinder when r = 1 inch and h = 4 inches

Given

h = 4 inches

r = 1 inch

Using the formula to determine the volume of the cylinder

V = πr²h

V = 3.14×(1)²×(4)

V = 3.14 × 1 × 4

V = 12.56

V ≈ 13 (nearst cubic inch)

Therefore, the volume of cylinder when h = 4 inches and r = 1 inch will be:

V ≈ 13 cubic inches (nearest cubic inch)

Determining the Volume of the cylinder when r = 2 inches and h = 4 inches

Given

h = 4 inches

r = 2 inch

Using the formula to determine the volume of the cylinder

V = πr²h

V = 3.14×(2)²×(4)

V = 3.14 × 4 × 4

V = 50.24

V ≈ 50 (nearst cubic inch)

Therefore, the volume of cylinder when h = 4 inches and r = 2 inches will be:

V ≈ 50 cubic inches (nearest cubic inch)

Determining the Volume of the cylinder when r = 3 inches and h = 4 inches

Given

h = 4 inches

r = 3 inch

Using the formula to determine the volume of the cylinder

V = πr²h

V = 3.14×(3)²×(4)

V = 3.14 × 9 × 4

V = 113.04

V ≈ 113 (nearst cubic inch)

Therefore, the volume of cylinder when h = 4 inches and r = 3 inches will be:

V ≈ 113 cubic inches (nearest cubic inch)

Therefore, we complete the table conclude such as:

Radius Volume

1 13

2 50

3 113

5 0

2 years ago

9. An article was sold at a profit of 12%. Had it been sold for Nu 80 more, there would be a profit of

Kamila [148]

Answer:

The cost price of the article was Nu 1,000

The original selling price was Nu 1,120

The second selling price was Nu 1,200

Step-by-step explanation:

System of Equations

Let's call:

x = Original selling price of the article

y = Cost of the article

The first condition implies that the difference between the selling price and the cost price (the profit) is 12%. Recall the profit % is always calculated with respect to the cost, that is, the profit at the first condition is:

0.12y = Original profit

Setting up the equation, we have:

$x-y=0.12y$

The second condition states the selling price is 80 Nu more than before, that is:

x+80= Second selling price of the article

y = Cost of the article (it doesn't change)

The profit of this condition is 20%, thus:

0.2y = Second profit

This produces a second equation:

$x+80-y=0.2y$

Let's put both equations together to form a system of equations:

$x-y=0.12y$

$x+80-y=0.2y$

Operating on both equations:

$x=1.12y$

$x=1.2y-80$

Equating both equations, we have an equation with only y's:

$1.12y=1.2y-80$

Subtracting 1.2y on each side:

$1.12y-1.2y=-80$

Operating:

$-0.08y=-80$

Solving:

$\displaystyle y=\frac{-80}{-0.08}=1,000$

a)

The cost price of the article was Nu 1,000

b) The selling price of the article will be calculated in both cases:

Original selling price: x=1.12y= 1.12*1000=1,120

The original selling price was Nu 1,120

The second selling price was x+80=1,200

The second selling price was Nu 1,200

8 0

3 years ago

What is the length of the line segment whose endpoints are (1, 1) and (3, - 3)

Shtirlitz [24]

Answer:

length= √[ (a-c)^2 + (b-d)^2 ]

Step-by-step explanation:

5 0

2 years ago