Given f(x) = –5x + 1, what is f(

A water faucet runs at a rate of 4/5 gallon per 1/5 minute. What is the unit rate of the faucet? *

vodomira [7]

Answer:

<h2>4gallons per minute</h2>

Step-by-step explanation:

Step one:

the unit rate is the amount of water per unit of time

Given data

4/5 gallon to decimal= 0.8gallon

1/5 minute decimal= 0.2 minute

We are told that 0.8 gallons run in 0.2 minute

then x gallon will run in 1 minute

cross muliply we have

x=0.8/0.2

x=4

this means that in one minutes 4gallons will run in the faucet

The unit rate is 4gallons per minute

6 0

3 years ago

Look at the following expression:

user100 [1]

Answer: The last option, Stacy is incorrect because she should multiply 2 and 2 first and then subtract 4 from 12.

Step-by-step explanation:

We must follow the Order of Operations, also known as PEMDAS. See attached. Multiplication comes before subtraction, but Stacy subtracted 2 from 12 when she should have multiplied 2 by 2. This means the answer to your question is;

Stacy is incorrect because she should multiply 2 and 2 first and then subtract 4 from 12.

5 0

2 years ago

2 1/2 divided by 5/8

Whitepunk [10]

Answer:

4

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$