Answer:
meaning the answer isnt there
Step-by-step explanation:
Step-by-step explanation:
f(x) = (x-2)/(3x+3). Let y = f(x).
Then y = (x-2)/(3x+3).
y(3x+3) = x - 2
3xy + 3y = x - 2
3xy - x = -3y - 2
x(3y-1) = -(3y+2)
x = -(3y+2)/(3y-1)
Hence, the inverse of f(x) is -(3x+2)/(3x-1).
Better to write that as:
-1
cos [ sqrt(3) / 2 ]
since the cosine is defined as "adjacent side over hypotenuse," we know that the adj. side is sqrt(3) and that the hyp is 2. The primary solution will be in Quadrant I because the adj. side is positive.
Think: which angle in Q I has adj. side equal to sqrt(3) and hyp equal to 2?
That'd be 30 degrees. Unfortunately, that's not one of your answer choices. Thus, reflect that angle in the positive x-axis; you'll end up with a ray whose positive angle is 330 degrees.
I'd suggest you ensure that you've copied this problem down correctly.
sqrt(3)
Did you mean sqrt(3/2) or did you mean ---------- ??
2
