Answer:
Yes, this graph is absolutely right for the function y = 
.
Step-by-step explanation:
firstly we will calculate amplitude, period, phase shift, and vertical shift.
Use the standard form 
to calculate the values of amplitude, period, phase shift, vertical shift.
here a = 2
b = 2
c = 0
d = -3
Amplitude = |a| = 2
period = 
= 
= 
phase shift = 
= 0
and vertical shift = d = -3
so, by using this information, if we plot the graph then the graph obtained will be same as the given graph.
Pythagorean Theorem: a^2 + b^2 = c^2
-A and B are legs of the triangle
-C is the hypotenuse
#1.
6^2 + 8^2 = c^2
36 + 64 = c^2
100 = c^2
c = 10
#2.
5^2 + 12^2 = c^2
25 + 144 = c^2
169 = c^2
c = 13
#4.
10^2 + 4^2 = c^2
100 + 16 = c^2
116 = c^2
c = 
#5.
15^2 + 9^2 = c^2
225 + 81 = c^2
306 = c^2
c = 
#6.
120^2 + b^2 = 150^2
14400 + b^2 = 22500
b^2 = 8100
b = 90
#7.
144^2 + b^2 = 194^2
20736 + b^2 = 37636
b^2 = 16900
b = 130
Hope this helps!! :)
You can determine if things are parallel if the lines will eventually meet or not. M and N are one line while P and Q are also a line. Therefore, we can say P is one line while M is also one line. The answer would be is that they are parallel, the two lines will not crash with one another. To show your work as if they are parallel, you can continue the lines down and write a note saying they won't collide or you just say they won't collide and are parallel lines.
Answer:
see explanation
Step-by-step explanation:
Part 1
The n th term of a geometric sequence is
= a
where a is the first term and r the common ratio
Given 
= 128, then
a
= 128, that is
32a = 128 ( divide both sides by 32 )
a = 4 ← first term
Part 2
= 4
= 4 × 1048576 = 4194304
