Answer:
7 mins
Step-by-step explanation:
Current speed of Joes Car = 65.5 mph
We have to find the time interval for which the car exceeded the speed limit of 55 mph.
While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph
We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence
1.50 mph is increased in 1 minute
1 mph will be increase in 
minutes
Hence
10.50 mph will be increased in 
minutes
Hence joes car was exceeding the limit of 55 mph for 7 minutes.
Answer:r-1
Step-by-step explanation:
(-r-5)-(-2r-4) Or (-r-5)-(-2r-4)
-r+-5+2r+4. -r-5+2r+4
r-1 r-1
You bring down the first Parentheses Then have to multiply the (implied 1) -1•-2=2 and -1•-4=4 and do the math regularly
Answer:
Regression Line is given by,
y = 22.909 + 0.209 x
The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Step-by-step explanation:
The equation of Regression equation is of the form of:
y = a + bx
where, a is intercept and b is slope
The formula for a and b is given by,
Here, ∑X = 1149.8, ∑Y = 377.2, ∑XY = 93115.95, ∑X² = 320246.72
Thus, a = 22.909
and b = 0.209
Thus, Regression Line is given by,
y = 22.909 + 0.209 x
Thus, The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Now plotting these line:
